Trio Breeding Scheme Planner

Convert a target number of correct-genotype weanlings into a concrete trio, dam, and cage count using strain-specific wean rates and the full genotyping yield pipeline.

Breeding & GeneticsMouse StrainsClient-Side
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Load example trio breeding scheme planner data to see the full workflow

Production Targets

Number of correct-genotype weanlings you need for downstream experiments.

0.25 = het × het → homo (1/4); 0.5 = het × wt → het (1/2); 1.0 = no selection.

Standard inbred — average 6 pups/litter, 85% wean rate.

Fraction of pups that yield a clean genotyping result. Default 0.95.

Override the strain default if your colony differs.

Breeding Plan

Trios needed
11
1 male + 2 females
Dams needed
21
at 6 pups/litter
Pups (with buffer)
125
25% breeding-failure buffer
Total cages
11
1 cage per trio

Yield Math

Effective yield = 0.25 × 0.85 × 0.95 = 0.202

Pups needed = ⌈20 / 0.202⌉ = 100

+ 25% buffer → 125 pups → ⌈125 / 6⌉ = 21 dams → 11 trios.

  • Planning a breeding cohort for an experimental study with a target N
  • Estimating cage and per-diem costs for a new project
  • Comparing breeding strategies (trio vs pair) for cost analysis
  • Onboarding new lab members to colony management math
  • Forecasting weanling supply across different mouse strains

Don't use for

  • For IVF or rederivation workflows (different math)
  • For very rare genotypes (<1%) — use a custom breeding scheme
  • For congenic backcrossing — use the backcross calculator instead

Trio Breeding Basics

What is a trio?

One stud male housed continuously with two breeding females in the same cage. The male services both females; the females cycle independently and produce offset litters.

Why trios beat pairs

A trio occupies one cage but produces ~50% more pups per cage per month than a monogamous pair. Cage cost, husbandry time, and per-diem charges scale with cage count, so trios are ~50% more cost-efficient per pup.

When trios fail
  • Two dams give birth on the same day → litters compete for milk, mortality climbs
  • One dam dominates and stresses the other → poor breeding from the subordinate
  • Male is too young or too old → lower fertility
  • BALB/c males that fight when introduced to multiple females

Switch to monogamous pairs for any of these.

The Yield Equation

The full pipeline from breeding pair to usable weanling has three loss factors:

1. Genotype frequency

Only a fraction of pups have the genotype you want. For het ×\times het → homozygote, that's 1/4. For dihybrid → double homozygote, that's 1/16.

2. Wean rate

Of all pups born, some die before weaning. C57BL/6J runs ~85%; BALB/c runs ~75%; CD-1 runs ~90%. The dead pups don't make it to genotyping.

3. Genotyping success

PCR fails on a few percent of samples (poor DNA, contaminated tubes). Default is 95% — i.e., 5% of weanlings need re-snipping or are lost from the count.

Effective yield = genotype ×\times wean rate ×\times genotyping success

For a het ×\times het cross on B6 with default genotyping: 0.25 ×\times 0.85 ×\times 0.95 = 0.20. So you need ~5 pups born for every correct-genotype weanling — and that's before the breeding-failure buffer.

Frequently Asked Questions